Python内置函数 - zip

1, zip(可迭代对象1, 可迭代对象2...)

from collections.abc import Iterator

my_list_1 = [1, 2, 3, 4]
my_list_2 = [6, 7, 8]
result = zip(my_list_1, my_list_2) # 该迭代器返回tuple
print(type(result)) # <class 'zip'>
print(isinstance(result, Iterator)) # True

for i_tuple in result:
    print(i_tuple, type(i_tuple))

结果：

(1, 6) <class 'tuple'>
(2, 7) <class 'tuple'>
(3, 8) <class 'tuple'>

 

from collections.abc import Iterator

my_list_1 = [1, 2, 3, 4]
my_list_2 = [6, 7, 8]
result = zip(my_list_1, my_list_2) # 该迭代器返回tuple
print(type(result)) # <class 'zip'>
print(isinstance(result, Iterator)) # True

for i, j in result:
    print(i, type(i), j, type(j))

结果：

1 <class 'int'> 6 <class 'int'>
2 <class 'int'> 7 <class 'int'>
3 <class 'int'> 8 <class 'int'>

 

zip+*Iterator

用1个参数a接收，得到的就是zip对象

my_list_1 = [1, 2, 3, 4]
my_list_2 = [6, 7, 8]
result = zip(my_list_1, my_list_2) # 该迭代器返回tuple

a = zip(*result) # 等同于zip((1, 6), (2, 7), (3, 8))
print(type(a)) # <class 'zip'>

用匹配的参数接收（这边是2个），就是实际元素

my_list_1 = [1, 2, 3, 4]
my_list_2 = [6, 7, 8]
result = zip(my_list_1, my_list_2) # 该迭代器返回tuple

# *result: 展开迭代器, 拿到3个tuple, (1, 6), (2, 7), (3, 8)
a, b = zip(*result) # 等同于zip((1, 6), (2, 7), (3, 8))
print(a, type(a), b, type(a)) # (1, 2, 3) <class 'tuple'> (6, 7, 8) <class 'tuple'>