http://projecteuler.net上的试题答案

1.

print sum([n for n in range(1000) if n%3 == 0 or n%5 == 0])

2.

x=y=1
sum=0
while x<4000000:
    x,y=y,x+y
    if y%2 == 0:
        sum = sum + y
print sum

3.

4.

5.

6.

7.

9.

10.

13.

15.

16.

print reduce(lambda x,y:int(x)+int(y),list(str(2**1000)))

18.

20.

24.

25.

26.

28. ∑(16n^2-28n+16) 其中求和从n=1到501.

67. 同18