用dubbo时遇到的一个序列化的坑

  首先,这是标题党,问题并不是出现在序列化上,这是报错的一部分:

Caused by: com.alibaba.dubbo.remoting.RemotingException: Failed to send response: Response [id=24, version=2.0.0, status=20, event=false, error=null, result=RpcResult [result=xxxService$7@57e8ec64, exception=null]], cause: java.lang.RuntimeException: Serialized class xxxService must implement java.io.Serializable
 Java field: final xxxService xxxService$7.this$0
java.lang.RuntimeException: Serialized class xxxService must implement java.io.Serializable
 Java field: final xxxService xxxService$7.this$0
    at com.alibaba.com.caucho.hessian.io.JavaSerializer$FieldSerializer.serialize(JavaSerializer.java:315)
    at com.alibaba.com.caucho.hessian.io.JavaSerializer.writeInstance(JavaSerializer.java:263)
    at com.alibaba.com.caucho.hessian.io.JavaSerializer.writeObject(JavaSerializer.java:227)
    at com.alibaba.com.caucho.hessian.io.Hessian2Output.writeObject(Hessian2Output.java:408)
    at com.alibaba.dubbo.common.serialize.support.hessian.Hessian2ObjectOutput.writeObject(Hessian2ObjectOutput.java:92)
    at com.alibaba.dubbo.rpc.protocol.dubbo.DubboCodec.encodeResponseData(DubboCodec.java:210)

  报了错的是注册给dubbo的service端,代码类似这样(https://github.com/saaavsaaa/warn-report/blob/master/src/test/java/TestObjectInstance.java):

class SService{
    public A getA(){
        A a = new A(){{setN("dto");}};
        return a;
    }
}

class A{
    protected String n;

    public A(){
        n = "a";
    }

    public String getN() {
        return n;
    }

    public void setN(String n) {
        this.n = n;
    }
}
    @Test
    public void testSerializ(){
        SService s = new SService();
        A a = s.getA();
        System.out.println(a.getN());
    }

   这什么情况,虽然通过dubbo的网络传输是需要序列化的,但是你要我把sevice也实现Serializable是闹哪样,然后紧接着发现了个更奇怪的事:第二行Java field: final xxxService xxxService$7.this$0,哪来的field,哪也没定义过这玩意,怎么还有个this...,当然上面的精简代码是能一眼猜到问题在哪,不过原本的代码好几百行,查的这个费劲,其实看到这个精简代码大家也基本可以猜到问题在哪了:

A a = new A(){{setN("dto");}};

代码改成:

class SService{
    public A getA(){
//        A a = new A(){{setN("dto");}};
        A a = new A();
        a.setN("dto");
        return a;
    }
}

结果就正常了:

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posted @ 2016-11-24 15:54  draculav  阅读(35815)  评论(4编辑  收藏  举报