1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)

import java.util.Scanner;

public class first {
    public static void main(String[] args) {
        System.out.println("请输入一个年份");
        Scanner sc = new Scanner(System.in);
        int year = sc.nextInt();
        if ((year % 4 == 0 && year % 100 != 00) || (year % 400 == 0)) {
            System.out.println(year + "是一个闰年");
        } else {
            System.out.println(year + "是一个平年");
        }
    }


}

  2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.

import java.util.Scanner;

public class first {
    public static void main(String[] args) {
        System.out.println("请输入会员卡号");
        Scanner sc = new Scanner(System.in);
        int id = sc.nextInt();
        if (id % 1000 / 100 % 3 == 0) {
            System.out.println("幸运会员");
        } else {
            System.out.println("不是");
        }

    }

}

  3.已知函数,输入x的值,输出对应的y的值.
        x + 3 ( x > 0 )
y =  0 ( x = 0 )
        x*2 –1 ( x < 0 )

import java.util.Scanner;

public class first {
    public static void main(String[] args) {
        System.out.println("请输入x的值");
        Scanner sc = new Scanner(System.in);
        int x = sc.nextInt();
        int y;
        if (x>0) {
            y=x+3;
            System.out.println("y的值为:"+y);
        } else if (x==0){
            y=0;
            System.out.println("y的值为:"+y);
        }else if (x<0){
            y=x*2-1;
            System.out.println("y的值为:"+y);
        }

    }

}

  4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)

import java.util.Scanner;

public class first {
    public static void main(String[] args) {
        System.out.println("三角形的三个边长");
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        int c = sc.nextInt();

        if ((a + b) > c && (a + c) > b && (b + c) > a) {
            System.out.println("可以构成三角形");
        }
        System.out.println("不可以构成三角型");

    }

}