datatable select distinct【摘自网络】
3.0 lamdba 表达式
2.0 提供了2个totable
1.DataTable.DefaultView.ToTable(表名,是否,字段集合)
2.DataTable.DefaultView.ToTable(是否,字段集合)
DataTable d = dt.DefaultView.ToTable(true, new string[] { "CLOTHESTYPE" });
1.0
DataTable dt = dqDetail.DataTable;
string[] fileds = { "CLOTHESTYPE" };//DISTINCT字段数组
DataTable newdt = this.SelectDistinct(dt, fileds);
/// <summary>
/// 返回执行Select distinct后的DataTable
/// </summary>
/// <param name="SourceTable">源数据表</param>
/// <param name="FieldNames">字段集</param>
/// <returns></returns>
private DataTable SelectDistinct(DataTable SourceTable, params string[] FieldNames)
{
object[] lastValues;
DataTable newTable;
DataRow[] orderedRows;
if (FieldNames == null || FieldNames.Length == 0)
throw new ArgumentNullException("FieldNames");
lastValues = new object[FieldNames.Length];
newTable = new DataTable();
foreach (string fieldName in FieldNames)
newTable.Columns.Add(fieldName, SourceTable.Columns[fieldName].DataType);
orderedRows = SourceTable.Select("", string.Join(",", FieldNames));
foreach (DataRow row in orderedRows)
{
if (!fieldValuesAreEqual(lastValues, row, FieldNames))
{
newTable.Rows.Add(createRowClone(row, newTable.NewRow(), FieldNames));
setLastValues(lastValues, row, FieldNames);
}
}
return newTable;
}
private bool fieldValuesAreEqual(object[] lastValues, DataRow currentRow, string[] fieldNames)
{
bool areEqual = true;
for (int i = 0; i < fieldNames.Length; i++)
{
if (lastValues[i] == null || !lastValues[i].Equals(currentRow[fieldNames[i]]))
{
areEqual = false;
break;
}
}
return areEqual;
}
private DataRow createRowClone(DataRow sourceRow, DataRow newRow, string[] fieldNames)
{
foreach (string field in fieldNames)
newRow[field] = sourceRow[field];
return newRow;
}
private void setLastValues(object[] lastValues, DataRow sourceRow, string[] fieldNames)
{
for (int i = 0; i < fieldNames.Length; i++)
lastValues[i] = sourceRow[fieldNames[i]];
}