洛谷 P1001 A+B Problem

题目描述

输入两个整数a,b,输出它们的和(|a|,|b|<=10^9)。 注意 1、pascal使用integer会爆掉哦!

2、有负数哦!

3、c/c++的main函数必须是int类型,而且最后要return 0。这不仅对洛谷其他题目有效,而且也是noip/noi比赛的要求!

好吧,同志们,我们就从这一题开始,向着大牛的路进发。

“任何一个伟大的思想,都有一个微不足道的开始。”

输入输出格式

输入格式:

 

两个整数以空格分开

 

输出格式:

 

一个数

 

输入输出样例

输入样例#1:
20 30
输出样例#1:
50

 

 

 

#include <algorithm>
#include <cstdio>
#include <vector>
#include <queue>

using namespace std;
int a,b;
long long ans;
class Segmenttree
{
    private:
        int dis[3];
        struct Segment
        {
            int l,r,sum;
            Segment *ch[2];
            Segment()
            {
                ch[0]=ch[1]=NULL;
            }
        };
        void build(Segment *&k,int l,int r)
        {
            k=new Segment;
            k->l=l;k->r=r;
            if(l==r) {k->sum=dis[l];return;}
            int mid=(l+r)>>1;
            build(k->ch[0],l,mid);
            build(k->ch[1],mid+1,r);
            k->sum=k->ch[0]->sum+k->ch[1]->sum;
        }
        int Tree_Query(Segment *&k,int l,int r)
        {
            if(k->l==l&&k->r==r) return k->sum;
            int mid=(k->l+k->r)>>1;
            if(l>mid) return Tree_Query(k->ch[1],l,r);
            else if(r<=mid) return Tree_Query(k->ch[0],l,r);
            else return Tree_Query(k->ch[0],l,mid)+Tree_Query(k->ch[1],mid+1,r);
        }
    public:
        int get()
        {
            Segment *root=new Segment;
            dis[1]=a;
            dis[2]=b;
            build(root,1,2);
            return Tree_Query(root,1,2);
        }
};
class Segmenttree segment;
class chairmantree
{
    private:
        int rs[500],ls[500],sum[500],rt[3],v1[3],v2[3],tot,Size;
        int build(int l,int r)
        {
            int now=++tot;
            sum[now]=0;
            if(l==r) return now;
            int mid=(l+r)>>1;
            ls[now]=build(l,mid);
            rs[now]=build(mid+1,r);
            return now;
        }
        inline int rank(int x) {return lower_bound(v2+1,v2+1+Size,x)-v2;}
        void update(int l,int r,int x,int &y,int t)
        {
            y=++tot;
            sum[y]=sum[x]+1;
            if(l==r) return;
            ls[y]=ls[x];
            rs[y]=rs[x];
            int mid=(l+r)>>1;
            if(t<=mid) update(l,mid,ls[x],ls[y],t);
            else update(mid+1,r,rs[x],rs[y],t);
        }
        int ask(int l,int r,int x,int y,int k)
        {
            if(l==r) return l;
            int mid=(l+r)>>1;
            if(sum[ls[y]]-sum[ls[x]]>=k) return ask(l,mid,ls[x],ls[y],k);
            else {k-=sum[ls[y]]-sum[ls[x]];return ask(mid+1,r,rs[x],rs[y],k);} 
        }
    public:
        int get()
        {
            v1[1]=v2[1]=a;
            v1[2]=v2[2]=b;
            sort(v2+1,v2+1+2);
            Size=unique(v2+1,v2+1+2)-v2-1;
            rt[0]=build(1,Size);
            for(int i=1;i<=2;++i) update(1,Size,rt[i-1],rt[i],rank(v1[i]));
            return v2[ask(1,Size,rt[0],rt[2],1)]+v2[ask(1,Size,rt[0],rt[2],2)];
        }
};
class chairmantree chairman;
class BIT
{
    private:
        int tag[3],n;
        inline int lowbit(int x) {return x&(-x);}
        void modify(int x,int y)
        {
            for(;x<=n;x+=lowbit(x))
            tag[x]+=y;
        }
        int ask(int x)
        {
            int ret=0;
            for(;x;x-=lowbit(x)) ret+=tag[x];
            return ret;
        }
    public:
        int get()
        {
            n=2;
            tag[1]=tag[2]=0;
            modify(1,a);
            modify(2,b);
            return ask(2)-ask(0);
        }
};
class BIT bit;
class SPFA
{
    private:
        vector<pair<int,int> >G[4];
        int dis[4],n;
        bool vis[4];
        void Spfa(int s)
        {
            queue<int>q;
            for(int i=1;i<=n;++i) vis[i]=0,dis[i]=0x7fffffff;
            dis[s]=0;
            q.push(s);
            for(int now;!q.empty();)
            {
                now=q.front();
                q.pop();
                vis[now]=0;
                for(int i=0;i<G[now].size();++i)
                {
                    int v=G[now][i].first,w=G[now][i].second;
                    if(dis[v]>dis[now]+w)
                    {
                        dis[v]=dis[now]+w;;
                        if(!vis[v])
                        {
                            vis[v]=1;
                            q.push(v);
                        }
                    }
                }
            }
        }
    public:
        int get()
        {
            n=3;
            G[1].push_back(make_pair(2,a));
            G[2].push_back(make_pair(3,b));
            Spfa(1);
            return dis[3];
        }
};
class SPFA spfa;
class FLOYD
{
    private:
        #define inf 0x3f3f3f3f
        inline int min(int a,int b) {return a>b?b:a;}
        int f[4][4],n;
        int floyd()
        {
            for(int k=1;k<=n;++k)
             for(int i=1;i<=n;++i)
              for(int j=1;j<=n;++j)
               f[i][j]=min(f[i][j],f[i][k]+f[k][j]);
            return f[1][3];
        }
    public:
        int get()
        {
            n=3;
            for(int i=1;i<=n;++i)
             for(int j=1;j<=n;++j)
              f[i][j]=(i!=j)*inf;
            f[1][2]=a;
            f[2][3]=b;
            return floyd();
        }
};
class FLOYD floyd;
class DINIC
{
    private:
        inline int min(int a,int b) {return a>b?b:a;}
        #define inf 0x3f3f3f3f
        int s,t,nextt[15],to[15],flow[15],head[5],cnt,dep[5];
        bool bfs(int s,int t)
        {
            queue<int>q;
            for(int i=s;i<=t;++i) dep[i]=-1;
            q.push(s);
            dep[s]=0;
            for(int now;!q.empty();)
            {
                now=q.front();
                q.pop();
                for(int i=head[now];i;i=nextt[i])
                {
                    int v=to[i];
                    if(dep[v]==-1&&flow[i])
                    {
                        dep[v]=dep[now]+1;
                        if(v==t) return true;
                        q.push(v);
                    }
                }
            }
            return false;
        }
        int dfs(int now,int t,int Limit)
        {
            if(now==t||!Limit) return Limit;
            int f,ret=0;
            for(int i=head[now];i;i=nextt[i])
            {
                int v=to[i];
                if(dep[v]==dep[now]+1&&flow[i]&&(f=dfs(v,t,min(Limit,flow[i]))))
                {
                    flow[i]-=f;
                    flow[i^1]+=f;
                    Limit-=f;
                    ret+=f;
                    if(!Limit) break;
                }
            }
            if(ret!=Limit) dep[now]=-1;
            return ret;
        }
        int dinic(int s,int t)
        {
            int ret=0;
            for(;bfs(s,t);ret+=dfs(s,t,inf));
            return ret;
        }
        void ins(int u,int v,int l)
        {
            nextt[++cnt]=head[u];
            to[cnt]=v;
            flow[cnt]=l;
            head[u]=cnt;
        }
    public:
        int get()
        {
            s=0;t=3;cnt=1;
            ins(s,1,a);
            ins(1,s,0);
            ins(s,2,b);
            ins(2,s,0);
            ins(1,t,a);
            ins(t,1,0);
            ins(2,t,b);
            ins(t,2,0);
            return dinic(s,t);
        }
};
class DINIC dinic;
class DP
{
    private:
        inline int max(int a,int b) {return a>b?a:b;}
        int f[4],v[4],w[4];
    public:
        int get()
        {
            v[1]=v[2]=1;
            w[1]=a;if(a<0) f[0]+=a,f[1]+=a,f[2]+=a;
            w[2]=b;if(b<0) f[0]+=b,f[1]+=b,f[2]+=b;
            for(int i=1;i<=2;++i)
             for(int j=2;j>=v[i];--j)
              f[j]=max(f[j-v[i]]+w[i],f[j]);
            return f[2];
        }
};
class DP dp;
class Kruskal
{
    private:
        int fa[4];
        struct node
        {
            int x,y,z;
            bool operator<(node a)const
            {
                return z<a.z;
            }
        }e[5];
        int find_(int x) {return x==fa[x]?x:fa[x]=find_(fa[x]);}
    public:
        int get()
        {
            int n=3,cnt=0;
            for(int i=1;i<=n;++i) fa[i]=i;
            e[++cnt].x=1;
            e[cnt].y=2;
            e[cnt].z=a;
            e[++cnt].x=2;
            e[cnt].y=3;
            e[cnt].z=b;
            sort(e+1,e+1+cnt);
            int num=0,ret=0;
            for(int i=1;i<=cnt;++i)
            {
                int fx=find_(e[i].x),fy=find_(e[i].y);
                if(fx!=fy)
                {
                    fa[fy]=fx;
                    num++;
                    ret+=e[i].z;
                    if(num==n-1) break;
                }
            }
            return ret;
        }
};
class Kruskal kruskal;
int Main()
{
    scanf("%d%d",&a,&b);
    ans+=segment.get();
    ans+=bit.get();
    ans+=chairman.get();
    ans+=spfa.get();
    ans+=floyd.get();
    ans+=dinic.get();
    ans+=dp.get();
    ans+=kruskal.get();
    printf("%lld\n",ans/8);
    return 0;
}
int sb=Main();
int main(int argc,char *argv[]){;}

 

posted @ 2017-09-15 16:50  杀猪状元  阅读(592)  评论(0编辑  收藏  举报