SQL-Split

CREATE   FUNCTION fn_Split(@sText nvarchar(4000), @sDelim varchar(20) = ' ')
RETURNS @retArray TABLE (idx smallint Primary Key, value varchar(8000))
AS
BEGIN
DECLARE @idx smallint,
@value nvarchar(4000),
@bcontinue bit,
@iStrike smallint,
@iDelimlength tinyint
IF @sDelim = 'Space'
BEGIN
SET @sDelim = ' '
END
SET @idx = 0
SET @sText = LTrim(RTrim(@sText))
SET @iDelimlength = DATALENGTH(@sDelim)
SET @bcontinue = 1
IF NOT ((@iDelimlength = 0) or (@sDelim = 'Empty'))
BEGIN
WHILE @bcontinue = 1
  BEGIN
--If you can find the delimiter in the text, retrieve the first element and
--insert it with its index into the return table.

  IF CHARINDEX(@sDelim, @sText)>0
  BEGIN
  SET @value = SUBSTRING(@sText,1, CHARINDEX(@sDelim,@sText)-1)
    BEGIN
    INSERT @retArray (idx, value)
    VALUES (@idx, @value)
    END
 
--Trim the element and its delimiter from the front of the string.
  --Increment the index and loop.
SET @iStrike = DATALENGTH(@value) + @iDelimlength
  SET @idx = @idx + 1
  SET @sText = LTrim(Right(@sText,DATALENGTH(@sText) - @iStrike))
 
  END
  ELSE
  BEGIN
--If you can抰 find the delimiter in the text, @sText is the last value in
--@retArray.
SET @value = @sText
    BEGIN
    INSERT @retArray (idx, value)
    VALUES (@idx, @value)
    END
  --Exit the WHILE loop.
SET @bcontinue = 0
  END
  END
END
ELSE
BEGIN
WHILE @bcontinue=1
  BEGIN
  --If the delimiter is an empty string, check for remaining text
  --instead of a delimiter. Insert the first character into the
  --retArray table. Trim the character from the front of the string.
--Increment the index and loop.
  IF DATALENGTH(@sText)>1
  BEGIN
  SET @value = SUBSTRING(@sText,1,1)
    BEGIN
    INSERT @retArray (idx, value)
    VALUES (@idx, @value)
    END
  SET @idx = @idx+1
  SET @sText = SUBSTRING(@sText,2,DATALENGTH(@sText)-1)
 
  END
  ELSE
  BEGIN
  --One character remains.
  --Insert the character, and exit the WHILE loop.
  INSERT @retArray (idx, value)
  VALUES (@idx, @sText)
  SET @bcontinue = 0
  END
END
END
RETURN
END