5阶m序列
void echo32(int m)
{
printf("%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d\n",
(m & 2147483648)>> 31,
(m & 1073741824)>> 30,
(m & 536870912 )>> 29,
(m & 268435456 )>> 28,
(m & 134217728 )>> 27,
(m & 67108864 )>> 26,
(m & 33554432 )>> 25,
(m & 16777216 )>> 24,
(m & 8388608 )>> 23,
(m & 4194304 )>> 22,
(m & 2097152 )>> 21,
(m & 1048576 )>> 20,
(m & 524288 )>> 19,
(m & 262144 )>> 18,
(m & 131072 )>> 17,
(m & 65536 )>> 16,
(m & 32768 )>> 15,
(m & 16384 )>> 14,
(m & 8192 )>> 13,
(m & 4096 )>> 12,
(m & 2048 )>> 11,
(m & 1024 )>> 10 ,
(m & 512 )>> 9 ,
(m & 256 )>> 8 ,
(m & 128 )>> 7 ,
(m & 64 )>> 6 ,
(m & 32)>> 5,
(m & 16)>> 4,
(m & 8) >> 3,
(m & 4) >> 2,
(m & 2) >> 1,
m & 1);
}
void m5(int iv)
{
int i,j,input,output;
int m;
int reg;
//因为只有5个寄存器，所以只能有2^5-1=31组,排除全0
for(j=0;j<31;j++){
iv = iv & 31;
reg = iv == 0 ? ++iv : iv;
m = 0;
for(i=0;i<31;i++){
output = reg & 1;
input = (((reg & 4) >> 2) ^ output)<<4;
reg = (reg >> 1) | input;
//printf("%d",output);
m=((m<<1)|output)&2147483647;
//printf("%d\n",m);
//
}
iv++;
printf("%0x\n",m);
//echo32(m);
}
printf("\n");
}
