CODEVS1533 Fibonacci数列 (矩阵乘法)

嗯，，，矩阵乘法最基础的题了。

Program CODEVS1250;
type  arr=array[1..2,1..2] of longint;
var T,n,mo:longint;
    a,b:arr;
operator *(a,b:arr) c:arr;
var i,j,k,sum:longint;
begin
  fillchar(c,sizeof(c),0);
  for i:=1 to 2 do
    for j:=1 to 2 do
      begin
        sum:=0;
        for k:=1 to 2 do
          sum:=(sum+a[i,k]*b[k,j]) mod mo;
        c[i,j]:=sum;
      end;
  exit(c);
end;
procedure main;
var i,j:longint;
begin
  readln(n,mo);
  a[1,1]:=1; a[1,2]:=0; a[2,1]:=0; a[2,2]:=1;
  b[1,1]:=0; b[1,2]:=1; b[2,1]:=1; b[2,2]:=1;
  while n>0 do
    begin
      if n mod 2=1 then a:=a*b;
      n:=n div 2;    
      b:=b*b;    
    end;
  writeln((a[1,1]+a[1,2]) mod mo);
end;
begin
  readln(T);
  while T>0 do begin dec(T); main; end;
end.