mycode  54.81%

class Solution(object):
    def findPeakElement(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if len(nums) == 0:
            return None
        if len(nums) == 1 or nums[0]>nums[1] :
            return 0
        if nums[-1] > nums[-2]:
            return len(nums)-1
        
        for i in range(1,len(nums)-1):
            if nums[i] > nums[i-1] and nums[i] > nums[i+1]:
                return i
       

 

参考:

思路:题目中左右为负无穷这个条件可以用起来,把原列表扩增以下就可以把两端的情况合并在一个for循环讨论啦

import math
class Solution(object):
    def findPeakElement(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        
        nums = [-float('inf')] + nums + [-float('inf')]
        for i in range(1, len(nums)-1):
            if nums[i-1] < nums[i] > nums[i+1]:
                return i-1