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Python -- lambda, map, filter

 

 


 

lambda

f = lambda x : x * 2

f(5)


f = lambda x,y,z : x+y+z

f(2,1,3)

 

 


map

 

list(map(lambda x:x[0].upper()+x[1:].lower(), ['sQd', 'ZORO']))

#传入列表,首字母变大写,其余变小写

 


 

reduce

from functools import reduce

def add(x, y):
  return x + y

reduce(add, [1,2,3,4])
reduce(f, [x1, x2, x3, x4]) = f(f(f(x1, x2), x3), x4)

 


filter

list(filter(lambda n: n%2 == 1, [1,2,3,4,5]))

#保留奇数,舍弃偶数
list(filter(lambda s: s and s.strip(), ['S', '', None, 'b']))

#删除一个列表中的空元素

 


 

posted @ 2015-10-21 21:38  Roronoa__Zoro  阅读(183)  评论(0编辑  收藏  举报