Codeforces Round #293 (Div. 2)
摘要：
AVitaly and Strings题意：给定长度相等的字符串s，t，且s的字典序小于t，求一个字符串q字典序大于s小于t。分析：将字符串看做26进制的数，对s”+1“即可。#include #define pb push_back#define mp make_pair#define esp 1... 阅读全文
posted @ 2015-02-26 00:08 rootial 阅读(234) 评论(0) 推荐(0) 编辑
