LinearLayout遇到的问题——利用LinearLayout做横向滑动冲突

问题：当我添加两个TextView的时候，然后滑动，发现只生成了一个TextView。

就是

<?xml version="1.0" encoding="utf-8"?>
<com.maikefengchao.viewcompflict.HorzonScrollLinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="horizontal"
    tools:context="com.maikefengchao.viewcompflict.MainActivity">

    <TextView
        android:id="@+id/main_tv_first"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@android:color/holo_blue_light"
        android:text="我是第一页"
        android:gravity="center"/>

    <TextView
        android:id="@+id/main_tv_second"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@android:color/darker_gray"
        android:text="第二页"
        android:gravity="center"/>
</com.maikefengchao.viewcompflict.HorzonScrollLinearLayout>

public class HorzonScrollLinearLayout extends LinearLayout {
    private int mLastX;
    private int mLastY;
    private int mCurrentX;
    private int mCurrentY;
    private int mTouchLastX;
    private int mTouchLastY;


    public HorzonScrollLinearLayout(Context context) {
        super(context);
    }

    public HorzonScrollLinearLayout(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    public HorzonScrollLinearLayout(Context context, AttributeSet attrs, int defStyleAttr) {
        super(context, attrs, defStyleAttr);
    }

    @Override
    public boolean onTouchEvent(MotionEvent event) {
        int scrollX = (int) event.getX();
        int scrollY = (int) event.getY();
        switch (event.getAction()){
            case MotionEvent.ACTION_DOWN:
                break;
            case MotionEvent.ACTION_MOVE:
                int deltaX = mLastX - scrollX;
                scrollBy(deltaX,0);
                break;
            case MotionEvent.ACTION_UP:
                break;
        }
        mLastX = scrollX;
        mLastY = scrollY;
        return true;
    }

    @Override
    public boolean onInterceptTouchEvent(MotionEvent ev) {
        boolean isIntercept = false;
        mCurrentX = (int) ev.getX();
        mCurrentY = (int) ev.getY();

        switch (ev.getAction()){
            case MotionEvent.ACTION_DOWN:
                isIntercept = false;
                break;
            case MotionEvent.ACTION_MOVE:
                //往左滑动为正
                int deltaX = mLastX - mCurrentX;
                int deltaY = mLastY - mCurrentY;
                if(Math.abs(deltaX) > Math.abs(deltaY)){
                    isIntercept = true;
                }
                else {
                    isIntercept = false;
                }
                break;
            case MotionEvent.ACTION_UP:
                isIntercept = false;
                break;
        }
        mLastX = mCurrentX;
        mLastY = mCurrentY;
        return isIntercept;
    }

发生滑动的时候，只有第一个显示出来

为什么会这样子呢，因为我忘了LinearLayout的大小是屏幕的宽度，所以整体大小值有一个屏幕宽，第二个TextView因为第一个TextView占满的屏幕，根据LinearLayout的源码

就是当前容器的宽度大小 减去 上一子类View占用的控件，就是当前子类的可用空间。

解决办法：

1、在java文件中，将TextView加入LinearLayout中，并设置TextView的LayoutParam.width 为 屏幕宽度。

TextView textView = new TextView(this);
textView.getLayoutParams().width = screenWidth;
textView.getLayoutParams().height = screenHeight;

mHorzonScroll.addView(textView);