工作记录_mysql_AND优先级高于OR优先级

1.错误示例

SELECT 
	t.task_department_name, 
	COUNT(*) total_count,
	SUM(CASE WHEN status='done' THEN 1 ELSE 0 END) AS finish_count,
	SUM(CASE WHEN status<>'done' THEN 1 ELSE 0 END) AS unfinish_count
FROM `t_task` t
-- WHERE task_type = 'update' AND (task_department_name LIKE '%镇' OR task_department_name LIKE '%街')
WHERE t.task_department_name LIKE '%镇' 
OR t.task_department_name LIKE '%街' 
OR t.task_department_name LIKE '%机关'
AND t.task_type in ('create')
GROUP BY task_department_name

结果:该结果与预期不符(eg:秀全街总数应该是3个,并且没有完成的任务)

2。错误原因分析

AND优先级高于OR优先级,上面代码实际上下面这样的:
SELECT 
	t.task_department_name, 
	COUNT(*) total_count,
	SUM(CASE WHEN status='done' THEN 1 ELSE 0 END) AS finish_count,
	SUM(CASE WHEN status<>'done' THEN 1 ELSE 0 END) AS unfinish_count
FROM `t_task` t
-- WHERE task_type = 'update' AND (task_department_name LIKE '%镇' OR task_department_name LIKE '%街')
WHERE t.task_department_name LIKE '%镇' 
OR t.task_department_name LIKE '%街' 
OR (t.task_department_name LIKE '%机关'
AND t.task_type in ('create'))
GROUP BY task_department_name
也就是说:t.task_department_name LIKE '%机关'先和t.task_type in ('create')进行AND运算,这就是出错之处

3.错误解决:加括号明确优先级:

SELECT 
	t.task_department_name, 
	COUNT(*) total_count,
	SUM(CASE WHEN status='done' THEN 1 ELSE 0 END) AS finish_count,
	SUM(CASE WHEN status<>'done' THEN 1 ELSE 0 END) AS unfinish_count
FROM `t_task` t
-- WHERE task_type = 'update' AND (task_department_name LIKE '%镇' OR task_department_name LIKE '%街')
WHERE (t.task_department_name LIKE '%镇' 
OR t.task_department_name LIKE '%街' 
OR t.task_department_name LIKE '%机关')
AND t.task_type in ('create')
GROUP BY task_department_name

解决:

本文作者:远道而重任

本文链接:https://www.cnblogs.com/rong-xu-drum/p/17478384.html

版权声明:本作品采用知识共享署名-非商业性使用-禁止演绎 2.5 中国大陆许可协议进行许可。

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