摘要: var a = [0, 2, 3, 4]; a = a.map(function (i) { return i + 1; }).filter(function (i) { console.log(i) return i % 2 != 0; }); console.log(a); //3,5 阅读全文
posted @ 2018-03-15 15:11 velin 阅读(1600) 评论(0) 推荐(0) 编辑