[Icpc] zoj 1037 Gridland （water C++ / Java）

规律 :  偶数行或偶数列必定存在全部为1的路径把所有点连起来,  否则m行n列中存在 m*n-1个1 和 一个 sqrt(2) 的路径连起所有点

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <cstdlib>
#include <cmath>

using std::cin;
using std::cout;
using std::endl;
using std::string;

typedef string String;

int main() {
    int T;
    scanf("%d", &T);
    for (int i = 1; i <= T; i++) {
        int a, b;
        scanf("%d%d", &a, &b);
        printf("Scenario #%d:\n", i);
        if (((a * b) & 0x1) == 0) {
            printf("%.2f\n", (double)(a*b));
        }
        else {
            printf("%.2f\n", (double)(a*b) + 0.41);
        }
        printf("\n");
    }
    return 0;
}

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int T = in.nextInt();
        for (int i = 1; i <= T; i++) {
            int a = in.nextInt();
            int b = in.nextInt();
            System.out.printf("Scenario #%d:\n", i);
            if ((a * b) % 2 == 0) {
                System.out.printf("%.2f\n", (double)(a*b));
            }
            else {
                System.out.printf("%.2f\n", (double)(a*b - 1) + 1.41);
            }
            System.out.println();       
        }
    }
}