Color

http://poj.org/problem?id=2154

题意：经典polya题

解析：差别就是项链数目不定，采用欧拉函数，求出所有情况求解即可

 

// File Name: poj2154.cpp
// Author: bo_jwolf
// Created Time: 2013年10月08日 星期二 17:46:30

#include<vector>
#include<list>
#include<map>
#include<set>
#include<deque>
#include<stack>
#include<bitset>
#include<algorithm>
#include<functional>
#include<numeric>
#include<utility>
#include<sstream>
#include<iostream>
#include<iomanip>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<ctime>

using namespace std;

int Case;
typedef long long INT;

int eular( int n ){
	int i = 0;
	int ans = 1;
	for( int i = 2; i * i <= n; ++i ){
		if( n % i == 0 ){
			ans *= ( i - 1 );
			n /= i;
			while( n % i == 0 ){
				ans *= i;
				n /= i;
			}
		}
	}
	if( n > 1 )
		ans *= n - 1;
	return ans;
}

INT power( long long a, int b, int p ){
	INT ans = 1, temp = a;
	while( b ){
		if( b & 1 ){
			ans = ( ans * a )% p;
		}
		b >>= 1;
		a = ( a * a )% p;
        }
	return ans;
}

INT calc( int n, int p ){
	INT ans = 0;
	for( int i = 1; i * i <= n; ++i ){
		if( n % i == 0 ){
			ans = ( ans + eular( i ) * power( n , n / i - 1, p ) ) % p;
			if( i * i != n )
				ans = ( ans + eular( n / i ) * power( n, i - 1, p ) ) % p;
		}
	}
	return ans;
}

int main(){
	scanf( "%d", &Case );
	int i, n, p;
	for( int i = 1; i <= Case; ++i ){
		scanf( "%d%d", &n, &p );
		printf( "%I64d\n", calc( n, p ) );
	}

return 0;
}