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list_head实践

                ''~``
                        ( o o )
+------------------.oooO--(_)--Oooo.---------------------+
| Rick Wang                                             |
|                       E-mail: rikyok@gmail.com  |
| XIDIAN University     http://www.xdwy.com.cn    |
| Xi'an, China       (   )                               |
+---------------------\ (----(   )-----------------------+
                       \_)    ) /
                             (_/


  1
  2#include <stdio.h>
  3#include "list.h"
  4
  5struct test{
  6int a;
  7char b;
  8}
;
  9struct ts_hlist{
 10struct list_head member1;
 11int member2;
 12char member3;
 13double member4;
 14}
;
 15
 16LIST_HEAD(hellolist);
 17struct ts_hlist hellots;
 18struct ts_hlist * rs;
 19int main(void){
 20
 21struct test t1;
 22t1.a=8;
 23t1.b='z';
 24char *pchar="testok";
 25int i=0;
 26printf("length of int:%d char:%d double:%d long:%d\n",sizeof(int),sizeof(char),sizeof(double),sizeof(long));
 27printf("Address of t1 is:%p\nddd member of a is:%d\n member of b is:%c\n",&t1,t1.a,t1.b);
 28printf("Address of pchar is:%p\nvalue of pchar is:%s\n",pchar,pchar);
 29for(;i<strlen(pchar);i++)
 30{
 31  printf("Address of member of pchar in pos %d is %p  ,value of pchar in pos%d is:%c\n",i,pchar+i,i,pchar[i]);
 32}

 33printf("address base=0\n,than the address of a:%d\naddress of b:%d\n"&((struct test *)0)->a,&((struct test *)0)->b) ;
 34
 35
 36printf("If the NULL struct as 0 of ts_hlist is given,then the size of 0based willbe:like this:\n\n\n\n");
 37printf("   struct ts_hlist as NULL \n");
 38printf("%u --->|__________|\n",&( ((struct ts_hlist *)0)->member1)  );
 39printf("      |__________|\n");
 40printf("      |__________|\n");
 41printf("      |__________|\n");
 42printf("      |__________|\n");
 43printf("      |__________|\n");
 44printf("      |__________|\n");
 45printf("      |__________|\n");  
 46printf("%u --->|__________|\n",&( ((struct ts_hlist *)0)->member2) );
 47printf("      |__________|\n");
 48printf("      |__________|\n");
 49printf("      |__________|\n");
 50printf("%u--->|__________|\n",&( ((struct ts_hlist *)0)->member3) );
 51printf("      |__________|\n");
 52printf("      |__________|\n");
 53printf("      |__________|\n");
 54printf("%u--->|__________|\n",&( ((struct ts_hlist *)0)->member4) );
 55printf("      |__________|\n");
 56printf("      |__________|\n");
 57printf("      |__________|\n");
 58printf("      |__________|\n");
 59printf("      |__________|\n");
 60printf("      |__________|\n");
 61printf("      |__________|\n");
 62
 63printf("                          \n\n");
 64printf("  struct ts_hlist as allocate space\n");
 65int j=0;
 66
 67printf(" size of  ts_hlist struct is %d\n",sizeof(struct ts_hlist));
 68for(;j<sizeof(struct ts_hlist);j++)
 69{
 70  printf("     |__________|<--%p\n",&hellots+(unsigned long)j);
 71}

 72printf(" the address of head(type of head_list) is:%p\n",hellolist);
 73
 74hellots.member2=3;
 75hellots.member3='A';
 76hellots.member4=44.33;
 77list_add_tail(&hellots.member1,&hellolist);
 78rs=list_entry(&hellots.member1,struct ts_hlist,member1);
 79printf("  the address of member1 is: %p\n",&hellots+(unsigned long)&( ((struct ts_hlist *)0)->member1) );
 80printf("  the address of member2 is: %p\n",&hellots+(unsigned long)&( ((struct ts_hlist *)0)->member2) );
 81printf("  the address of member3 is: %p\n",&hellots+(unsigned long)&( ((struct ts_hlist *)0)->member3) );
 82printf("  the address of member4 is: %p\n",&hellots+(unsigned long)&( ((struct ts_hlist *)0)->member4) );
 83printf(" Now we'll test the value area of ts_hlist>>>>>\n");
 84printf("  member2 of rs is:%d\n", rs->member2);
 85printf("  member3 of rs is:%c\n", rs->member3);
 86printf("  member4 of rs is:%g\n", rs->member4);
 87}

 88
 89
 90Result:
 91
 92
 93If the NULL struct as 0 of ts_hlist is given,then the size of 0based willbe:like this:
 94
 95
 96   struct ts_hlist as NULL
 970 --->|__________|
 98      |__________|
 99      |__________|
100      |__________|
101      |__________|
102      |__________|
103      |__________|
104      |__________|
1058 --->|__________|
106      |__________|
107      |__________|
108      |__________|
10912--->|__________|
110      |__________|
111      |__________|
112      |__________|
11316--->|__________|
114      |__________|
115      |__________|
116      |__________|
117      |__________|
118      |__________|
119      |__________|
120      |__________|
121
122
123  struct ts_hlist as allocate space
124 size of  ts_hlist struct is 24
125     |__________|<--0x8049d7c
126     |__________|<--0x8049d94
127     |__________|<--0x8049dac
128     |__________|<--0x8049dc4
129     |__________|<--0x8049ddc
130     |__________|<--0x8049df4
131     |__________|<--0x8049e0c
132     |__________|<--0x8049e24
133     |__________|<--0x8049e3c
134     |__________|<--0x8049e54
135     |__________|<--0x8049e6c
136     |__________|<--0x8049e84
137     |__________|<--0x8049e9c
138     |__________|<--0x8049eb4
139     |__________|<--0x8049ecc
140     |__________|<--0x8049ee4
141     |__________|<--0x8049efc
142     |__________|<--0x8049f14
143     |__________|<--0x8049f2c
144     |__________|<--0x8049f44
145     |__________|<--0x8049f5c
146     |__________|<--0x8049f74
147     |__________|<--0x8049f8c
148     |__________|<--0x8049fa4
149 the address of head(type of head_list) is:0x8049c74
150  the address of member1 is0x8049d7c
151  the address of member2 is0x8049e3c
152  the address of member3 is0x8049e9c
153  the address of member4 is0x8049efc
154 Now we'll test the value aear of ts_hlist>>>>>
155  member2 of rs is:3
156  member3 of rs is:A
157  member4 of rs is:44.33
posted on 2006-12-29 17:23  riky  阅读(908)  评论(0编辑  收藏  举报

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