实验室每日一题WP-11月28日

打开题目，是一串熟悉的编码 Brainf**k

 

 去解码得到：awsl，作为2.zip的解压密码。

打开re.txt，是一个函数，于是尝试把v11~v23的值求出。

        v11[0] = 67;
        v11[1] = 90;
        v11[2] = 57;
        v11[3] = 100;
        v12 = 109;
        v13 = 113;
        v14 = 52;
        v15 = 99;
        v16 = 56;
        v17 = 103;
        v18 = 57;
        v19 = 71;
        v20 = 55;
        v21 = 98;
        v22 = 65;
        v23 = 88;

按照顺序排列：67 90 57 100 109 113 52 99 56 103 57 71 55 98 65 88

按照ASCII转换得到：CZ9dmq4c8g9G7bAX

尝试了一下是re1.rar的压缩密码

打开re1.txt，是一个异或函数。于是反过来

#include <iostream>
using namespace std;
int main(){
    char flag[33] = { 0x66,0x0A,0x6B,0x0C,0x77,0x26,0x4F,0x2E,0x40,0x11,0x78,0x0D,0x5A,0x3B,0x55,0x11,0x70,0x19,0x46,0x1F,0x76,0x22,0x4D,0x23,0x44,0x0E,0x67,6,0x68,0x0F,0x47,0x32,0x4F };
    for (int i = 32; i >=1 ; i--) {
        flag[i] ^= flag[i - 1];
    }
    cout << flag;
}

得到flag

flag{QianQiuWanDai_YiTongJiangHu}