Compare Version Numbers
Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
注意一个特例: 1 和 1.0。
所以 在比较完对应的位数之后,还要查看多的位数是不是均为0.
还有就是在split(".") 时候,由于.是正则表达式中的符号,所以要转置。
1 public class Solution { 2 public int compareVersion(String version1, String version2) { 3 String[] parts1 = version1.split("\\."); 4 String[] parts2 = version2.split("\\."); 5 int len1 = parts1.length; 6 int len2 = parts2.length; 7 int i = 0; 8 for(; i < len1 && i < len2; i ++){ 9 if(Integer.valueOf(parts1[i]) > Integer.valueOf(parts2[i])) return 1; 10 if(Integer.valueOf(parts2[i]) > Integer.valueOf(parts1[i])) return -1; 11 } 12 if(len1 > len2){ 13 while(i < len1){ 14 if(Integer.valueOf(parts1[i++]) != 0) return 1; 15 } 16 }else if(len1 < len2){ 17 while(i < len2){ 18 if(Integer.valueOf(parts2[i++]) != 0) return -1; 19 } 20 } 21 return 0; 22 } 23 }
posted on 2015-01-15 15:21 Step-BY-Step 阅读(217) 评论(0) 编辑 收藏 举报