.ne2.0开发winform应用程序时,输入状态总是变成全角的问题
客户反应我们的程序每次要输入东西,都要将输入状态从全角换回半角,调了大半天,没解决,于是搜了一下,发现是MS的BUG,于是下了网上公布的补丁,解决了问题,把搜到的解决方案摘下来。 nbsp;
至VS2005测试版以来就一直存在这个问题,在WinForm应用程序中和Visual Studio 2005开发环境中,一切换窗口,中文输入法就会变成全角。微软终于发布补丁程序了。
关于全角输入法Bug的官方文档 KB925488:
http://support.microsoft.com/default.aspx/kb/925488/
但是官方没有提供下载地址。
需要补丁的朋友可以从这儿下载:http://www.joyblog.cn/attachments/month_0702/ndp20-kb925488-x86.rar
方法一:
Form的Pain和遍历Control的Enter方法。
首先,我们为了使您原有的代码更简洁,我们把所要做的步骤封装到一个单独的类中,类代码如下:
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using System;
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using System.Runtime.InteropServices;
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namespace MyDemo
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{
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public static class clsIme
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{
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//声明一些API函数
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[DllImport("imm32.dll")]
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public static extern IntPtr ImmGetContext(IntPtr hwnd);
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[DllImport("imm32.dll")]
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public static extern bool ImmGetOpenStatus(IntPtr himc);
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[DllImport("imm32.dll")]
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public static extern bool ImmSetOpenStatus(IntPtr himc, bool b);
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[DllImport("imm32.dll")]
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public static extern bool ImmGetConversionStatus(IntPtr himc, ref int lpdw, ref int lpdw2);
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[DllImport("imm32.dll")]
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public static extern int ImmSimulateHotKey(IntPtr hwnd, int lngHotkey);
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public const int IME_CMODE_FULLSHAPE = 0x8;
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public const int IME_CHOTKEY_SHAPE_TOGGLE = 0x11;
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//重载SetIme,传入Form
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public static void SetIme(Form frm)
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{
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frm.Paint += new PaintEventHandler(frm_Paint);
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ChangeAllControl(frm);
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}
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//重载SetIme,传入Control
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public static void SetIme(Control ctl)
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{
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ChangeAllControl(ctl);
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}
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//重载SetIme,传入对象句柄
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public static void SetIme(IntPtr Handel)
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{
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ChangeControlIme(Handel);
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}
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private static void ChangeAllControl(Control ctl)
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{
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//在控件的的Enter事件中触发来调整输入法状态
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ctl.Enter += new EventHandler(ctl_Enter);
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//遍历子控件,使每个控件都用上Enter的委托处理
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foreach (Control ctlChild in ctl.Controls)
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ChangeAllControl(ctlChild);
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}
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static void frm_Paint(object sender, PaintEventArgs e)
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{
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/*有人问为什么使用Pain事件,而不用Load事件或Activated事件,是基于下列考虑:
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* 1、在您的Form中,有些控件可能是运行时动态添加的
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* 2、在您的Form中,使用到了非.NET的OCX控件
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* 3、Form调用子Form的时候,Activated事件根本不会触发 */
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ChangeControlIme(sender);
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}
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//控件的Enter处理程序
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static void ctl_Enter(object sender, EventArgs e)
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{
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ChangeControlIme(sender);
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}
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private static void ChangeControlIme(object sender)
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{
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Control ctl = (Control)sender;
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ChangeControlIme(ctl.Handle);
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}
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//下面这个函数才是真正检查输入法的全角半角状态
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private static void ChangeControlIme(IntPtr h)
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{
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IntPtr HIme = ImmGetContext(h);
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if (ImmGetOpenStatus(HIme)) //如果输入法处于打开状态
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{
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int iMode = 0;
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int iSentence = 0;
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bool bSuccess = ImmGetConversionStatus(HIme, ref iMode, ref iSentence); //检索输入法信息
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if (bSuccess)
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{
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if ((iMode & IME_CMODE_FULLSHAPE) > 0) //如果是全角
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ImmSimulateHotKey(h, IME_CHOTKEY_SHAPE_TOGGLE); //转换成半角
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}
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}
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}
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}
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}
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有人问为什么使用Pain事件,而不用Load事件或Activated事件,我是基于下列考虑:
1、在您的Form中,有些控件可能是运行时动态添加的
2、在您的Form中,使用到了非.NET的OCX控件
3、Form调用子Form的时候,Activated事件根本不会触发
使用这个类的方法为:
在您的界面中,在Load的时候,在里面加上这样一句话:
clsIme.SetIme(this);
方法二:
使用继承的方法。
首先,建立一个独立的类如下:
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using System;
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using System.Collections.Generic;
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using System.ComponentModel;
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using System.Data;
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using System.Collections;
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using System.Drawing;
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using System.Text;
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using System.Windows.Forms;
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using System.Runtime.InteropServices;
10![](https://www.cnblogs.com/Images/OutliningIndicators/None.gif)
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namespace MyDemo
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{
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public class ImeForm:System.Windows.Forms.Form
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{
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//声明一些API函数
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[DllImport("imm32.dll")]
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public static extern IntPtr ImmGetContext(IntPtr hwnd);
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[DllImport("imm32.dll")]
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public static extern bool ImmGetOpenStatus(IntPtr himc);
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[DllImport("imm32.dll")]
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public static extern bool ImmSetOpenStatus(IntPtr himc, bool b);
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[DllImport("imm32.dll")]
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public static extern bool ImmGetConversionStatus(IntPtr himc, ref int lpdw, ref int lpdw2);
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[DllImport("imm32.dll")]
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public static extern int ImmSimulateHotKey(IntPtr hwnd, int lngHotkey);
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private const int IME_CMODE_FULLSHAPE = 0x8;
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private const int IME_CHOTKEY_SHAPE_TOGGLE = 0x11;
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//重载Form的OnActivated
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protected override void OnActivated(EventArgs e)
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{
base.onActivated(e);
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IntPtr HIme = ImmGetContext(this.Handle);
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if (ImmGetOpenStatus(HIme)) //如果输入法处于打开状态
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{
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int iMode = 0;
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int iSentence = 0;
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bool bSuccess = ImmGetConversionStatus(HIme, ref iMode, ref iSentence); //检索输入法信息
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if (bSuccess)
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{
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if ((iMode & IME_CMODE_FULLSHAPE) > 0) //如果是全角
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ImmSimulateHotKey(this.Handle, IME_CHOTKEY_SHAPE_TOGGLE); //转换成半角
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}
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}
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}
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}
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}
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