摘要: #includeint main(void){ int count,i,n; double grade,total; printf("Enter n:"); scanf("%d",&n); total=0; count=0; for(i=1;i<=n;i++){ printf("Enter grade #%d ",i); scanf("%lf",&grade); total=total+grade; if(grade<60){ count++; } ... 阅读全文
posted @ 2013-10-03 22:36 执于一念 阅读(111) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int number; printf("Enter a number:"); scanf("%d",&number); if(number%2==0){ printf("The number is even.\n"); } else{ printf("The number is odd.\n"); } return 0;} 阅读全文
posted @ 2013-10-03 13:15 执于一念 阅读(92) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int mynumber=38; int yournumber; printf("Input yournumber:"); scanf("%d",&yournumber); if(yournumber==mynumber) printf("OK! you are right!\n"); else if(yournumber>mynumber) printf("Sorry!yournumber is bigger than mynumber!\n"); . 阅读全文
posted @ 2013-10-03 13:06 执于一念 阅读(81) 评论(0) 推荐(0) 编辑
摘要: #includedouble fact(int n);int main(void){ int i,n; double result; printf("Enter n:"); scanf("%d",&n); for(i=0;i<=n;i++){ result=fact(i); printf("%d!=%.0f\n",i,result); } return 0;}double fact(int n){ int i; double product; product=1; for(i=... 阅读全文
posted @ 2013-10-03 12:50 执于一念 阅读(88) 评论(0) 推荐(0) 编辑
摘要: #include#includeint main(void){ int i,n; double power; printf("Enter n:"); scanf("%d",&n); for(i=0;i<=n;i++){ power=pow(2,i); printf("pow(2,%d)=%.0f\n",i,power); } return 0;} 阅读全文
posted @ 2013-10-03 12:29 执于一念 阅读(97) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double product; printf("Enter n:"); scanf("%d",&n); product=1; for(i=1;i<=n;i++){ product=product*i; } printf("product=%.0f\n",product); return 0;} 阅读全文
posted @ 2013-10-03 12:19 执于一念 阅读(73) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int denominator,flag,i,n; double item,sum; printf("Enter n:"); scanf("%d",&n); flag=1; denominator=1; sum=0; for(i=1;i<=n;i++){ item=flag*1.0/denominator; sum=sum+item; flag=-flag; denominator=denominator+2; } prin... 阅读全文
posted @ 2013-10-03 11:59 执于一念 阅读(93) 评论(0) 推荐(0) 编辑
摘要: #include;int main(void){ int i,n,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=sum+i; } printf("Sum of numbers from 1 to %d is %d\n",n,sum); return 0;} 阅读全文
posted @ 2013-10-03 11:45 执于一念 阅读(64) 评论(0) 推荐(0) 编辑