求所有的函数 f: R → R,使得对任意 x, y ∈ R 都有 (x + y)·[f(x) - f(y)] = (x - y)·f(x + y).
posted @ 2023-12-07 23:33
posted @ 2023-12-07 23:33
posted @ 2023-06-22 14:00
posted @ 2023-03-08 22:48
posted @ 2022-11-19 22:57
posted @ 2022-10-03 15:56
posted @ 2022-09-10 14:11
posted @ 2022-08-24 23:35
posted @ 2022-07-30 17:18
posted @ 2022-06-26 10:07
posted @ 2022-06-05 21:14
posted @ 2022-05-29 22:45
posted @ 2022-04-26 22:53
posted @ 2022-04-16 18:32
posted @ 2022-04-11 23:49
posted @ 2021-09-12 12:38