Eclipse+Jersey实现RESTful服务接口(简单列子)

web.xml 配置

<servlet>
    <servlet-name>jerseyRestService</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.webservice.resfull</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
    <servlet-mapping>
        <servlet-name>jerseyRestService</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

实体类

package com.webservice.resfull;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.MediaType;

@Path("hello")
public class HelloResource {

    @GET
    @Produces(MediaType.TEXT_PLAIN)
    public String sayHello() {
        return "hello,jersey";
    }
    
    @GET
    @Path("hi")
    public String sayHiTo(@QueryParam("name") String name) {
        return "hello To " + name;
    }

}

 

maven配置

        <dependency>
     <groupId>com.sun.jersey</groupId>
     <artifactId>jersey-server</artifactId>
     <version>1.17.1</version>
</dependency>
<dependency>
     <groupId>com.sun.jersey</groupId>
     <artifactId>jersey-core</artifactId>
     <version>1.17.1</version>
</dependency>
<dependency>
     <groupId>com.sun.jersey</groupId>
     <artifactId>jersey-servlet</artifactId>
     <version>1.17.1</version>
</dependency>

 

测试:

浏览器输入

http://localhost:8080/xxx/rest/hello    (其中xxx是你的项目名)

结果页面输出:hello,jersey

浏览器输入:
http://localhost:8080/xxx/rest/hello/hi?name=tom
结果页面输出:hello To tom

注意事项:

web.xml中com.webservice.resfull 是指你的java类的包路径

posted @ 2020-10-28 16:46  爱跳舞的程序员  阅读(460)  评论(0编辑  收藏  举报