BZOJ2054 疯狂的馒头

还是离线把操作倒过来做，于是每个馒头只要看最后一种颜色就好了

如果一个馒头已经有颜色了，就把它并到右边的馒头的集合里去

 

 1 /**************************************************************
 2     Problem: 2054
 3     User: rausen
 4     Language: C++
 5     Result: Accepted
 6     Time:3268 ms
 7     Memory:39776 kb
 8 ****************************************************************/
 9  
10 #include <cstdio>
11 #include <algorithm>
12  
13 using namespace std;
14 const int N = 1e6 + 5;
15  
16 int c[N], fa[N];
17 int n, m, p, q;
18  
19 int find_f(int x) {
20     return x == fa[x] ? x : fa[x] = find_f(fa[x]);
21 }
22  
23 int main() {
24     int i, j, x, y;
25     scanf("%d%d%d%d", &n, &m, &p, &q);
26     for (i = 1; i <= n + 1; ++i) fa[i] = i;
27     for (i = m; i; --i) {
28         x = (1ll * i * p + q) % n + 1, y = (1ll * i * q + p) % n + 1;
29         if (x > y) swap(x, y);
30         for (j = find_f(x); j <= y; j = find_f(j))
31             c[j] = i, fa[j] = j + 1;
32     }
33     for (i = 1; i <= n; ++i)
34         printf("%d\n", c[i]);
35     return 0;
36 }
View Code

 

posted on 2015-03-09 22:30  Xs酱~  阅读(193)  评论(0)  编辑  收藏  举报