看看就发现了是道一眼题、、然后蒟蒻写了1h、、
先tarjan,然后缩点重新建图,最后扫一遍就可以了、、
(为什么加inline比不加要慢、、为什么调用全局变量比开局部变量要慢、、都是开O2的原因嘛!!!>_<)
1 /************************************************************** 2 Problem: 1051 3 User: rausen 4 Language: C++ 5 Result: Accepted 6 Time:48 ms 7 Memory:2132 kb 8 ****************************************************************/ 9 10 #include <cstdio> 11 #include <algorithm> 12 13 using namespace std; 14 const int N = 10005; 15 const int M = 50005; 16 struct edges{ 17 int next, to; 18 }e[M], E[M]; 19 int n, m; 20 int first[N], FIRST[N], tot, TOT; 21 int low[N], dfn[N], s[N], w[N], cnt, top; 22 int Cnt[N], num; 23 bool vis[N], inq[N]; 24 25 inline int read(){ 26 int x = 0; 27 char ch = getchar(); 28 while (ch < '0' || ch > '9') 29 ch = getchar(); 30 31 while (ch >= '0' && ch <= '9'){ 32 x = x * 10 + ch - '0'; 33 ch = getchar(); 34 } 35 return x; 36 } 37 38 inline void add_edge(int x, int y){ 39 e[++tot].next = first[x]; 40 first[x] = tot; 41 e[tot].to = y; 42 } 43 44 inline void ADD_EDGE(int x, int y){ 45 E[++TOT].next = FIRST[x]; 46 FIRST[x] = TOT; 47 E[TOT].to = y; 48 } 49 50 void DFS(int p){ 51 low[p] = dfn[p] = ++cnt; 52 vis[p] = inq[p] = 1; 53 s[++top] = p; 54 int x, y; 55 for (x = first[p]; x; x = e[x].next) 56 if (!vis[(y = e[x].to)]){ 57 DFS(y); 58 low[p] = min(low[p], low[y]); 59 }else 60 if (inq[y]) low[p] = min(low[p], dfn[y]); 61 if (low[p] == dfn[p]){ 62 ++num, y = 0; 63 while (y != p){ 64 inq[ (y = s[top--])] = 0; 65 w[y] = num; 66 ++Cnt[num]; 67 } 68 } 69 } 70 71 void rebuild_graph(){ 72 int x, y; 73 for (int i = 1; i <= n; ++i) 74 for (x = first[i]; x; x = e[x].next) 75 if (w[i] != w[(y = e[x].to)]) 76 ADD_EDGE(w[i], w[y]); 77 } 78 79 void tarjan(){ 80 for (int i = 1; i <= n; ++i) 81 if (!vis[i]) DFS(i); 82 rebuild_graph(); 83 } 84 85 int work(){ 86 int res = 0; 87 for (int i = 1; i <= num; ++i) 88 if (!FIRST[i]){ 89 if (res) return 0; 90 else res = Cnt[i]; 91 } 92 return res; 93 } 94 95 int main(){ 96 n = read(), m = read(); 97 int X, Y; 98 for (int i = 1; i <= m; ++i){ 99 X = read(), Y = read(); 100 add_edge(X, Y); 101 } 102 tarjan(); 103 printf("%d\n", work()); 104 return 0; 105 }
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