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起thread时，运行报错terminate called without an active exception

2017-12-12 17:22  nigaopeng  阅读(14088)  评论(0)  编辑  收藏  举报

I am getting a C++ error with threading:

terminate called without an active exception
Aborted

How to reproduce that error:

 1 #include <iostream>
 2 #include <stdlib.h>
 3 #include <string>
 4 #include <thread>
 5 using namespace std;
 6 void task1(std::string msg){
 7   cout << "task1 says: " << msg;
 8 }
 9 int main() { 
10   std::thread t1(task1, "hello"); 
11   return 0;
12 }

Compile and run:

el@defiant ~/foo4/39_threading $ g++ -o s s.cpp -pthread -std=c++11
el@defiant ~/foo4/39_threading $ ./s
terminate called without an active exception
Aborted (core dumped)

You get that error because you didn't join or detach your thread.

One way to fix it, join the thread like this:

#include <iostream>
#include <stdlib.h>
#include <string>
#include <thread>
using namespace std;
void task1(std::string msg){
  cout << "task1 says: " << msg;
}
int main() { 
  std::thread t1(task1, "hello"); 
  t1.join();
  return 0;
}

Then compile and run:

el@defiant ~/foo4/39_threading $ g++ -o s s.cpp -pthread -std=c++11
el@defiant ~/foo4/39_threading $ ./s
task1 says: hello

The other way to fix it, detach it like this:

#include <iostream>
#include <stdlib.h>
#include <string>
#include <unistd.h>
#include <thread>
using namespace std;
void task1(std::string msg){
  cout << "task1 says: " << msg;
}
int main() 
{ 
     {

        std::thread t1(task1, "hello"); 
        t1.detach();

     } //thread handle is destroyed here, as goes out of scope!

     usleep(1000000); //wait so that hello can be printed.
}

Compile and run:

el@defiant ~/foo4/39_threading $ g++ -o s s.cpp -pthread -std=c++11
el@defiant ~/foo4/39_threading $ ./s
task1 says: hello

Read up on detaching C++ threads and joining C++ threads.

 

总之，就是线程还在运行，主进程就退出导致了该错误。

原文链接：https://stackoverflow.com/questions/7381757/c-terminate-called-without-an-active-exception