66. Plus One
66. Plus One
题目
Given a non-negative integer represented as a non-empty array of digits, plus one to the integer.
You may assume the integer do not contain any leading zero, except the number 0 itself.
The digits are stored such that the most significant digit is at the head of the list.
解析
class Solution_66 {
public:
// 用一个数组表示一个整数的每一位,给这个整数+1,只有当前位为9时,才会有进位
vector<int> plusOne(vector<int> &digits) {
for (int i = digits.size() - 1; i >= 0; i--)
{
if (digits[i] == 9)
{
digits[i] = 0;
}
else
{
digits[i]++; //当前
return digits;
}
}
digits[0] = 1;
digits.push_back(0); //多一位就行
return digits;
}
};
题目来源
C/C++基本语法学习
STL
C++ primer