hdu 1004 shui
Let the Balloon Rise
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 65716 Accepted Submission(s): 24329
Problem Description
Contest
time again! How excited it is to see balloons floating around. But to
tell you a secret, the judges' favorite time is guessing the most
popular problem. When the contest is over, they will count the balloons
of each color and find the result.
This year, they decide to leave this lovely job to you.
This year, they decide to leave this lovely job to you.
Input
Input
contains multiple test cases. Each test case starts with a number N (0
< N <= 1000) -- the total number of balloons distributed. The next
N lines contain one color each. The color of a balloon is a string of
up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output
For
each case, print the color of balloon for the most popular problem on a
single line. It is guaranteed that there is a unique solution for each
test case.
Sample Input
5
green
red
blue
red
red
3
pink
orange
pink
0
Sample Output
red
pink
Author
WU, Jiazhi
Source
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import java.util.Scanner; //import java.util.HashMap; //import java.util.Map; //import java.util.Scanner; // //public class Main { // /** // * @param args // */ // public static void main(String[] args) { // // TODO Auto-generated method stub // Scanner sc = new Scanner(System.in); // while(true){ // int n = sc.nextInt(); // if(n==0) break; // String maxS=""; // int max=0; // Map<String, Integer> m = new HashMap<String,Integer>(); // for(int i=0; i<n; i++){ // String s = sc.next(); // if(m.containsKey(s)) // m.put(s, m.get(s)+1); // else m.put(s, 1); // if(m.get(s)>max){ // max=m.get(s); // maxS=s; // } // } // System.out.println(maxS); // } // } // //} public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); while(true){ int n=sc.nextInt(); if(n==0) break; String[] s = new String[n+1]; String pop=""; int ip = 0; for(int i=0; i<n; i++) s[i]=sc.next(); for(int i=0; i<n; i++){ String t = s[i]; int cnt=0; for(int j=0; j<n; j++) if(t.equals(s[j])) cnt++; if(cnt>ip){ ip=cnt; pop=t; } } System.out.println(pop); } } }