poj2481

树状数组,难点在于处理相同区间,对于相同区间,只是把答案直接拷贝过来,并把其加入树状数组,不可以直接在树状数组中求和。

View Code
#include <iostream>
#include
<cstdio>
#include
<cstdlib>
#include
<cstring>
#include
<algorithm>
using namespace std;

#define maxn 100005

struct Interval
{
int s, e;
int pos;
} interval[maxn];

int n;
int ar[maxn];
int ans[maxn];

bool operator <(const Interval &a, const Interval &b)
{
if (a.e == b.e)
return a.s < b.s;
return a.e > b.e;
}

int lowbit(int a)
{
return a & (-a);
}

void add(int i, int v)
{
for (; i < maxn; ar[i] += v, i += lowbit(i))
;
}

int sum(int i)
{
int s = 0;
for (; i > 0; s += ar[i], i -= lowbit(i))
;
return s;
}

int main()
{
//freopen("t.txt", "r", stdin);
while (scanf("%d", &n), n != 0)
{
memset(ar,
0, sizeof(ar));
for (int i = 0; i < n; i++)
{
scanf(
"%d%d", &interval[i].s, &interval[i].e);
interval[i].pos
= i;
}
sort(interval, interval
+ n);
for (int i = 0; i < n; i++)
{
if (i != 0 && interval[i].s == interval[i - 1].s && interval[i].e
== interval[i - 1].e)
{
ans[interval[i].pos]
= ans[interval[i - 1].pos];
}
else
ans[interval[i].pos]
= sum(interval[i].s + 1);
add(interval[i].s
+ 1, 1);
}
printf(
"%d", ans[0]);
for (int i = 1; i < n; i++)
printf(
" %d", ans[i]);
printf(
"\n");
}
return 0;
}

posted @ 2011-05-22 11:45  金海峰  阅读(408)  评论(0编辑  收藏  举报