MySQL之——GROUP BY分组取字段最大值
转载自:http://blog.csdn.net/l1028386804/article/details/54657412
假设有一个业务场景,需要查询用户登录记录信息,其中表结构如下:
- CREATE TABLE `tb` (
- `id` int(11) NOT NULL AUTO_INCREMENT,
- `uid` int(11) NOT NULL,
- `ip` varchar(16) NOT NULL,
- `login_time` datetime,
- PRIMARY KEY (`id`),
- KEY (`uid`)
- );
再来点测试数据:
- INSERT INTO tb SELECT null, 1001, '192.168.1.1', '2017-01-21 16:30:47';
- INSERT INTO tb SELECT null, 1003, '192.168.1.153', '2017-01-21 19:30:51';
- INSERT INTO tb SELECT null, 1001, '192.168.1.61', '2017-01-21 16:50:41';
- INSERT INTO tb SELECT null, 1002, '192.168.1.31', '2017-01-21 18:30:21';
- INSERT INTO tb SELECT null, 1002, '192.168.1.66', '2017-01-21 19:12:32';
- INSERT INTO tb SELECT null, 1001, '192.168.1.81', '2017-01-21 19:53:09';
- INSERT INTO tb SELECT null, 1001, '192.168.1.231', '2017-01-21 19:55:34';
表数据情况:
- +----+------+---------------+---------------------+
- | id | uid | ip | login_time |
- +----+------+---------------+---------------------+
- | 1 | 1001 | 192.168.1.1 | 2017-01-21 16:30:47 |
- | 2 | 1003 | 192.168.1.153 | 2017-01-21 19:30:51 |
- | 3 | 1001 | 192.168.1.61 | 2017-01-21 16:50:41 |
- | 4 | 1002 | 192.168.1.31 | 2017-01-21 18:30:21 |
- | 5 | 1002 | 192.168.1.66 | 2017-01-21 19:12:32 |
- | 6 | 1001 | 192.168.1.81 | 2017-01-21 19:53:09 |
- | 7 | 1001 | 192.168.1.231 | 2017-01-21 19:55:34 |
- +----+------+---------------+---------------------+
如果只需要针对用户查出其最后登录的时间,可以简单写出:
- SELECT uid, max(login_time)
- FROM tb
- GROUP BY uid;
- +------+---------------------+
- | uid | max(login_time) |
- +------+---------------------+
- | 1001 | 2017-01-21 19:55:34 |
- | 1002 | 2017-01-21 19:12:32 |
- | 1003 | 2017-01-21 19:30:51 |
- +------+---------------------+
若还需要查询用户最后登录时的其他信息,就不能用这种sql写了:
- -- 错误写法
- SELECT uid, ip, max(login_time)
- FROM tb
- GROUP BY uid;
- -- 错误写法
这样的语句是非SQL标准的,虽然能够在MySQL数据库中执行成功,但返回的却是未知的
(如果sql_mode开启了only_full_group_by,则不会执行成功。)
可能ip字段会取uid分组前的第一个row的值,显然不是所需信息
写法1
写一个子查询:
- SELECT a.uid, a.ip, a.login_time
- FROM tb a
- WHERE a.login_time in (
- SELECT max(login_time)
- FROM tb
- GROUP BY uid);
写法2
再或者换一个写法:
- SELECT a.uid, a.ip, a.login_time
- FROM tb a
- WHERE a.login_time = (
- SELECT max(login_time)
- FROM tb
- WHERE a.uid = uid);
顺便测了一下
在5.6以前的版本中,写法②这条sql在大数据量的情况下,执行计划不理想,目测性能不佳。
在5.6及以后的版本中,写法②这条sql会快很多,执行计划也有了改变
5.5.50:
- +----+--------------------+-------+------+---------------+------+---------+------+------+-------------+
- | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
- +----+--------------------+-------+------+---------------+------+---------+------+------+-------------+
- | 1 | PRIMARY | a | ALL | NULL | NULL | NULL | NULL | 7 | Using where |
- | 2 | DEPENDENT SUBQUERY | tb | ALL | uid | NULL | NULL | NULL | 7 | Using where |
- +----+--------------------+-------+------+---------------+------+---------+------+------+-------------+
5.6.30:
- +----+--------------------+-------+------+---------------+------+---------+------------+------+-------------+
- | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
- +----+--------------------+-------+------+---------------+------+---------+------------+------+-------------+
- | 1 | PRIMARY | a | ALL | NULL | NULL | NULL | NULL | 7 | Using where |
- | 2 | DEPENDENT SUBQUERY | tb | ref | uid | uid | 4 | test.a.uid | 1 | NULL |
- +----+--------------------+-------+------+---------------+------+---------+------------+------+-------------+
写法3
直接改成join性能会更加好:
- SELECT a.uid, a.ip, a.login_time
- FROM (SELECT uid, max(login_time) login_time
- FROM tb
- GROUP BY uid
- ) b JOIN tb a ON a.uid = b.uid AND a.login_time = b.login_time;
当然,结果都相同:
- +------+---------------+---------------------+
- | uid | ip | login_time |
- +------+---------------+---------------------+
- | 1003 | 192.168.1.153 | 2017-01-21 19:30:51 |
- | 1002 | 192.168.1.66 | 2017-01-21 19:12:32 |
- | 1001 | 192.168.1.231 | 2017-01-21 19:55:34 |
- +------+---------------+---------------------+