需经正则处理的字符串转数字

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<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <meta http-equiv="X-UA-Compatible" content="IE=edge">
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <title>Document</title>
</head>
<body>
  
</body>
<script type="text/javascript">
let initArr = ["10", "(-20)", "20","0","0","0"]
let handleArr1 = []
let handleArr2 = []
let handleArr3 = []
let handleArr4 = []
let handleArr5 = []
let handleArr6 = []
let handleArr7= []
let handleArr8= []
handleArr7 =initArr.join(",").match(/-?\d+/g)
handleArr7.forEach((item) => [
handleArr8.push((+item))
])

initArr.forEach((item, index) => {
  //检测数组元素的类型发现它们全都是'string'
  // console.log(typeof item);  //string
  if (item.search(/-[0-9]*[1-9][0-9]*/) != -1) {  //匹配负整数
    //字符串的match()方法会返回一个匹配结果组成的数组；["-20"]
    let temp = item.match(/-[0-9]*[1-9][0-9]*/)[0]
    handleArr1[index] = (+temp)
    handleArr2[index] = temp * 1
    handleArr3[index] = parseFloat(temp)
    handleArr4[index] = Math.floor(temp)
    handleArr5[index] = (~~temp)
    handleArr6[index] = parseInt(temp)
  } else if(item.search(/-?\d+/) != -1) {
    handleArr1[index] = (+item)
    handleArr2[index] = item * 1
    handleArr3[index] = parseFloat(item)
    handleArr4[index] = Math.floor(item)
    handleArr5[index] = (~~item)
    handleArr6[index] = parseInt(item)
  }

})
console.log("handleArr1" ,handleArr1); //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr2" ,handleArr1);  //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr3" ,handleArr1);  //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr4" ,handleArr1);  //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr5" ,handleArr1);  //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr6" ,handleArr6);  //[ 10, -20, 20, 0, 0, 0 ]
console.log("handleArr7" ,handleArr7);  //[ "10", "-20", "20", "0", "0", "0" ]
console.log("handleArr8" ,handleArr6);  //[ 10, -20, 20, 0, 0, 0 ]
</script>
</html>