4.18作业 及格与不及格

//及格和不及格
            //int[] a = new int[20];
          
            //for (int i = 1; i <= 20;i ++ )
            //{
            //    Console.Write("第{0}个学生的成绩为：",i );
            //    a[i - 1] = Convert .ToInt32( Console.ReadLine());
            //    if (a[i - 1] >= 60)
            //    {
            //        Console.WriteLine("及格");


            //    }
            //    else
            //    {
            //        Console.WriteLine("不及格");
            //    }

            //    }
            //int jige = 0;
            //for (int i = 1; i <= 20; i++)
            //{
            //    if (a[i - 1] >= 60)
            //    {
            //        jige++;
            //    }
            //}
            //Console.WriteLine("及格人数为"+jige );
            //int bujige = 0;
            //for (int i = 1; i <= 20; i++)
            //{
            //    if (a[i - 1] < 60)
            //    {
            //        bujige++;
            //    }
            //}
            //Console.WriteLine("不及格人数为" + bujige);
            //double  sum = 0;
            //for (int i = 1; i <= 20; i ++ )
            //{
            //    sum = sum + a[i -1];
            //}
            //Console.WriteLine("平均得分为"+sum/20);
            //及格和不及格

posted @ 2016-04-19 20:23  屈震  阅读(130)  评论(0)  编辑  收藏  举报