Java List<Map> 排序

 Collections.sort(sourceMap, new Comparator<Map<String, Object>>() {
            @Override
            public int compare(Map<String, Object> o1, Map<String, Object> o2) {
                return o1.get("fxdj").toString().compareTo(o2.get("fxdj").toString());
            }
        });

  

posted @ 2022-03-04 16:50  qukaige  阅读(619)  评论(0编辑  收藏  举报