摘要: 莫比乌斯函数 $$\mu(n) = \begin{cases} 1, & \text{if } n = 1 \ (-1)^k, & \text{if } n = p_1p_2 \ldots p_k \ 0, & \text{others} \end{cases}$$ 即: $\mu(1) = 1$ 阅读全文
posted @ 2022-11-09 11:25 quanjun 阅读(31) 评论(0) 推荐(0) 编辑