Codeforces Round #419 (Div. 2) ABC
python 2.7,用来熟悉Python
由于都是智障题,所以我也不讲述题意和题解,直接贴代码了……
A
import sys
h,m = map(int,raw_input().split(":"))
ans = 0
while True:
if h%10 == m/10 and h/10 == m%10:
break
ans = ans + 1
h,m = (h+m/59)%24,(m+1)%60
print ans
B
import sys
maxn = 200005
# class bit:
# def __init__(self):
# self.a = []
# for i in xrange(maxn):
# self.a.append(0)
# def lowbit(self,x):
# return x&(-x)
# def update(self,x,y):
# i=x
# while i < maxn:
# self.a[i] += y
# i+=self.lowbit(i)
# def get(self,x):
# ans=0
# i=x
# while i > 0:
# ans=ans+self.a[i]
# i-=self.lowbit(i)
# return ans
b = [0]*maxn
l = [0]*maxn
# Bit = bit()
n,k,m= map(int,raw_input().split())
for i in range(0,n):
a,b=map(int,raw_input().split())
l[a]=l[a]+1
l[b+1]=l[b+1]-1
tmp=0
ans=[0]
for i in range(1,maxn):
tmp=tmp+l[i]
ans2=0
if tmp >= k:
ans2=1
ans.append(ans2)
ans[i]=ans[i]+ans[i-1]
for i in range(0,m):
a,b=map(int,raw_input().split())
print ans[b]-ans[a-1]
C
import sys
def read():
return map(int,raw_input().split())
n,m=read()
g=[list(read()) for i in range(n)]
a=[g[i][0]-g[0][0] for i in range(n)]
b=[g[0][i]-g[0][0] for i in range(m)]
for i in range(n):
for j in range(1,m):
if g[i][j] - g[i][0] != b[j]:
print "-1"
exit()
for j in range(m):
for i in range(1,n):
if g[i][j] - g[0][j] != a[i]:
print "-1"
exit()
mn=min(min(i) for i in g)
mb=min(b)
for i in range(m):
b[i]-=mb
ma=min(a)
for i in range(n):
a[i]-=ma
if n<m:
for i in range(n):a[i]+=mn
else:
for i in range(m):b[i]+=mn
print(sum(a)+sum(b))
for i in range(n):
for j in range(a[i]):
print "row",i+1
for i in range(m):
for j in range(b[i]):
print "col",i+1