Codeforces Round #346 (Div. 2) A. Round House 水题

A. Round House

题目连接:

http://www.codeforces.com/contest/659/problem/A

Description

Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.

Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.

Illustration for n = 6, a = 2, b =  - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.

Input

The single line of the input contains three space-separated integers n, a and b (1 ≤ n ≤ 100, 1 ≤ a ≤ n,  - 100 ≤ b ≤ 100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.

Output

Print a single integer k (1 ≤ k ≤ n) — the number of the entrance where Vasya will be at the end of his walk.

Sample Input

6 2 -5

Sample Output

3

Hint

题意

给你一个环形轨道,你一开始在a,然后你走b步,问你在哪儿。

题解:

这个小心负数的情况,为了避免这个,我直接将a+=100*n,这样就不会有负数的情况了。

代码

#include<bits/stdc++.h>
using namespace std;

int main()
{
    long long n,a,b;
    cin>>n>>a>>b;a--;
    a=a+100*n;
    a=a+b;
    cout<<a%n+1<<endl;
}
posted @ 2016-03-31 17:13  qscqesze  阅读(430)  评论(0编辑  收藏  举报