Codeforces Round #281 (Div. 2) B. Vasya and Wrestling 水题

B. Vasya and Wrestling

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.

When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.

If the sequences of the awarded points coincide, the wrestler who performed the last technique wins. Your task is to determine which wrestler won.

Input

The first line contains number n — the number of techniques that the wrestlers have used (1 ≤ n ≤ 2·10⁵).

The following n lines contain integer numbers a_i (|a_i| ≤ 10⁹, a_i ≠ 0). If a_i is positive, that means that the first wrestler performed the technique that was awarded with a_i points. And if a_i is negative, that means that the second wrestler performed the technique that was awarded with ( - a_i) points.

The techniques are given in chronological order.

Output

If the first wrestler wins, print string "first", otherwise print "second"

Sample test(s)

Input

5
1
2
-3
-4
3

Output

second

Input

3
-1
-2
3

Output

first

Input

2
4
-4

Output

second

Note

Sequence x  =  x₁x₂... x_|x| is lexicographically larger than sequence y  =  y₁y₂... y_|y|, if either |x|  >  |y| and x₁  =  y₁,  x₂  =  y₂, ... ,  x_|y|  =  y_|y|, or there is such number r (r  <  |x|, r  <  |y|), that x₁  =  y₁,  x₂  =  y₂,  ... ,  x_r  =  y_r and x_{r  +  1}  >  y_{r  +  1}.

We use notation |a| to denote length of sequence a.

两个cha点：
LL和最后一发谁打谁赢

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
ll kiss[1000000];
ll kill[1000000];
int main()
{

    int n;
    cin>>n;
    ll ans1=0;
    ll ans2=0;
    int path1=0;
    int path2=0;
    int flag3=0;
    int num=0;
    for(int i=0;i<n;i++)
    {
        cin>>num;
        if(num<0)
        {
            kill[path2++]=-num;
            ans2-=num;
        }
        else
        {
            kiss[path1++]=num;
            ans1+=num;
        }
        if(i==n-1)
        {
            if(num<0)
                flag3=2;
            else
                flag3=1;
        }

    }
    //cout<<ans1<<" "<<ans2<<endl;
    int flag=0;
    if(ans1>ans2)
    {
        flag=1;
    }
    else if(ans2>ans1)
    {
        flag=2;
    }
    else
    {
        int len=min(path1-1,path2-1);
        for(int i=0;i<len+1;i++)
        {
            //cout<<kiss[i]<<" "<<kill[i]<<endl;
            if(kiss[i]>kill[i])
            {
                flag=1;
                break;
            }
            if(kill[i]>kiss[i])
            {
                flag=2;
                break;
            }
        }
        if(flag==0)
        {
            if(path1>path2)
                flag=1;
            else if(path2>path1)
                flag=2;
            else
                flag=flag3;
        }
    }
    if(flag==1)
        cout<<"first"<<endl;
    else
        cout<<"second"<<endl;

    return 0;
}