摘要: 一、打开文件 Stream myStream = null; OpenFileDialog openFileDialog1 = new OpenFileDialog(); openFileDialog1.InitialDirectory = "d:\\"; openFileDialog1.Filte 阅读全文
posted @ 2018-05-02 11:48 qqhfeng16 阅读(241) 评论(0) 推荐(0) 编辑