Length of Last Word

https://leetcode.com/problems/length-of-last-word/

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

调用String.sqilt(" ")来求解：

public class Solution {
    public  int lengthOfLastWord(String s) {
        String[]t=s.split(" ");
        if(t.length==0)return 0;
        return t[t.length-1].length();
    }
}

自己实现：

public class Solution {
    public static int lengthOfLastWord(String s) {
    if(s.equals("")) return 0;
    int len=s.length();
    int index=len;
    while(index>0&&s.charAt(--index)==' ');
    if(s.charAt(index)==' ') return 0;
    int cout=1;
    while(index>0&&s.charAt(--index)!=' '){cout++;}
        return cout;
    }
    public static void main(String[]args){
    System.out.println(lengthOfLastWord("  "));
    }
}