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[js] 过滤连续重复的元素

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            var uniqueInOrder = function(iterable) {
                if (iterable instanceof Array) {
                    var temp = [];
                    for (var i = 0; i < iterable.length; i++) {
                        if (iterable[i] !== iterable[i + 1]) {
                            temp.push(iterable[i]);
                        }
                    }
                    return temp;
                }
                if (typeof iterable === 'string') {
                    var temp = '';
                    for (var i = 0; i < iterable.length; i++) {
                        if (iterable[i] !== iterable[i + 1]) {
                            temp += iterable[i];
                        }
                    }
                    return temp.split('');
                }
            }
            var uniqueInOrder = function(iterable) {
                if (Array.isArray(iterable)) {
                    return iterable.filter((v, i) => v !== iterable[i + 1]);
                }
                if (typeof iterable === 'string') {
                    var iterable = iterable.split('');
                    return iterable.filter((v, i) => v !== iterable[i + 1])
                }
            }
            var uniqueInOrder = function(iterable) {
                return [].filter.call(iterable, (function(a, i) {
                    return iterable[i - 1] !== a
                }));
            }
            var uniqueInOrder = function(iterable) {
                return Array.prototype.reduce.call(iterable, function(a, b) {
                    if (a[a.length - 1] !== b) a.push(b);
                    return a;
                }, []);
            }
            console.log(uniqueInOrder([1, 2, 2, 3, 3]));
            console.log(uniqueInOrder('AAAABBBCCDAABBB'));
            console.log(uniqueInOrder('ABBCcAD'));

 

posted @ 2016-03-18 18:45  晴明桑  阅读(771)  评论(0编辑  收藏  举报