javascript取url的参数的方法
<script type="text/javascript"> function request(paras) { var url = location.href; var paraString = url.substring(url.indexOf("?")+1,url.length).split("&"); var paraObj = {} for (i=0; j=paraString[i]; i++){ paraObj[j.substring(0,j.indexOf("=")).toLowerCase()] = j.substring(j.indexOf("=")+1,j.length); } var returnValue = paraObj[paras.toLowerCase()]; if(typeof(returnValue)=="undefined"){ return ""; }else{ return returnValue; } } var title = request('title'); var dids = request('did'); show(dids,title); function show(dids,title){ $.ajax({ url: "http://www.xxx.com/index.php?ac=article&at=read&isajax=1", type: "get", data:{did:dids}, error: function(){ alert('Error loading XML document'); }, success: function(data,status){ // var obj = eval('(' + data + ')'); $("#content").html(data); $("#content img").css("width","100%"); $("#content img").css("height","auto"); // alert(title); // $("#article_title").html(title); } }); } </script>