412. Fizz Buzz

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]
数字转化为字符串

1.使用to_string

1 #include <iostream>
2 #include <string>
3 using namespace std;
4 int main() {
5     int a = 123;
6     string s = to_string(a);
7     cout << s;
8     return 0;
9 }

2.使用stringstream

#include <iostream>
#include <sstream>
using namespace std;
int main() {
    stringstream stream;
    string str;
    int a = 123;
    stream << a;
    stream >> str;
    cout << str;
    return 0;
}

3.如果是字符数组(使用sprintf)

 1 #include <iostream>
 2 #include <cstdio>
 3 using namespace std;
 4 int main() {
 5     char c[50] = "123";
 6     int a;
 7     sscanf(c, "%d", &a); // 不要忘记 “&”
 8     int b = 567;
 9     sprintf(c, "%d", b);
10     cout << a << endl << c;
11     return 0;
12 }
13 
14 /*
15 sscanf将字符数组转换为数字,输入到数字变量中
16 sprintf将数字转换为字符数组,输出到字符数组变量中
17 */
class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> result;
        for(int i = 1; i <= n; i++){
            if(i % 3 == 0){
                if(i % 5 == 0){
                    result.push_back("FizzBuzz");
                } else {
                    result.push_back("Fizz");
                }
            } else if(i % 5 == 0){
                result.push_back("Buzz");
            } else {
                result.push_back(to_string(i));
            }
        }
        return result;
    }
};

 

 
posted @ 2017-01-29 20:29  琴影  阅读(214)  评论(0编辑  收藏  举报