[leedcode 237] Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void deleteNode(ListNode node) {
        //时间复杂度就是O(1)
        //要删除的节点是node
        //直接将node->next的val值赋给node,然后删除node->next
        node.val=node.next.val;
        node.next=node.next.next;
    }
}

 

posted @ 2015-08-08 19:48  ~每天进步一点点~  阅读(105)  评论(0编辑  收藏  举报