[leedcode 227] Basic Calculator II
Implement a basic calculator to evaluate a simple expression string.
The expression string contains only non-negative integers, +
, -
, *
, /
operators and empty spaces . The integer division should truncate toward zero.
You may assume that the given expression is always valid.
Some examples:
"3+2*2" = 7 " 3/2 " = 1 " 3+5 / 2 " = 5
public class Solution { public int calculate(String s) { //使用sigh代表前一个运算符,利用栈保存加法或减法运算值,当遇到乘除时, //弹出栈顶进行运算,并将结果压栈,最后的结果时将栈中的元素进行相加 int res=0; int sum=0; char sigh='+'; Stack<Integer> stack=new Stack<Integer>(); for(int i=0;i<s.length();i++){ char c=s.charAt(i); if(Character.isDigit(c)){ sum=sum*10+c-'0'; } if(!Character.isDigit(c)&&s.charAt(i)!=' '||i==s.length()-1){ if(sigh=='+'){ stack.push(sum); }else if(sigh=='-'){ stack.push(-sum); }else if(sigh=='*'){ int t=stack.pop(); stack.push(t*sum); }else if(sigh=='/'){ int t=stack.pop(); stack.push(t/sum); } sum=0; sigh=c; } } while(!stack.isEmpty()){ res+=stack.pop(); } return res; } }