[leedcode 141] Linked List Cycle

Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

/**
 * Definition for singly-linked list.
 * class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public boolean hasCycle(ListNode head) {
        //双指针,一快一慢,绝对速度为1,如果相遇 有环,马上返回,fast==null或者fast为尾节点时,返回false
        if(head==null) return false;
        ListNode fast=head;
        ListNode slow=head;
        while(fast!=null&&fast.next!=null){
            fast=fast.next.next;
            slow=slow.next;
            if(fast==slow) return true;
        }
        return false;
    }
}

 

posted @ 2015-07-26 21:55  ~每天进步一点点~  阅读(105)  评论(0编辑  收藏  举报