[leedcode 133] Clone Graph
Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use#
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
/** * Definition for undirected graph. * class UndirectedGraphNode { * int label; * List<UndirectedGraphNode> neighbors; * UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); } * }; */ public class Solution { 使用深度优先搜索。这样可以递归实现,如果是宽度优先,就要额外使用queue容器。 关键点: 1 这里的clone需要深度拷贝,就是要使用new操作了 2 防止回路无限循环,就要使用hash表,这里使用map记录访问过的节点。因为这里的label应该是唯一的才对,所以可以直接使用label作为关键字就可以。 public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { if(node==null) return null; HashMap<Integer,UndirectedGraphNode> map=new HashMap<Integer,UndirectedGraphNode>(); return clone(node,map); } public UndirectedGraphNode clone(UndirectedGraphNode node,HashMap<Integer,UndirectedGraphNode> map){ if(map.containsKey(node.label)) return map.get(node.label); UndirectedGraphNode newNode=new UndirectedGraphNode(node.label); map.put(node.label,newNode);////注意标记的位置 for(UndirectedGraphNode n:node.neighbors){ newNode.neighbors.add(clone(n,map));///// } return newNode; } }