解析url 

from urllib.parse import urlparse


url_change = urlparse('https://i.cnblogs.com/EditPosts.aspx?opt=1')
#ParseResult(scheme='https', netloc='i.cnblogs.com', path='/EditPosts.aspx', params='', query='opt=1', fragment='')
scheme = url_change.scheme  #'https'
netloc = url_change.netloc  #'i.cnblogs.com'
posted @ 2020-06-10 18:05  乔儿  阅读(205)  评论(0)  编辑  收藏  举报