在xpath的xml路径中传入参数 

lables = ['nvbfge','cvbfg','nfsd','jklibn','dfgrt','muyh','ytug','nghmdf','gfhasfecxv']
for lable in lables:
    print(lable)
    urls_0 = response.xpath("//map[@name=$val]/area/@href",val=lable).extract()
    print(urls_0)
posted @ 2019-10-29 12:24  乔儿  阅读(351)  评论(0)  编辑  收藏  举报