python 选课系统
2018-12-07 11:07 小于漫谈 阅读(259) 评论(0) 编辑 收藏 举报
couser.py:
import sys,os
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
sys.path.append(BASE_DIR)
from core import main
if __name__ == '__main__': #__main__就是导入的模块,main,__name__是系统变量
a = main.Run() #实例化类
a.interactive() #调用类的方法
uid.py:
import hashlib
import time
def create_md():
m = hashlib.md5()
m.update(bytes(str(time.time()),encoding='utf-8')) #hash的数值
return m.hexdigest() #16进制的hash值
main.py:
import sys,os
import json
import pickle
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
sys.path.append(BASE_DIR)
from core import uid
#数据库文件路径
db_DIR = BASE_DIR + r"\db"
db_school = db_DIR + r"\school"
db_teacher = db_DIR + r"\student"
db_classes = db_DIR + r"\classes"
db_course = db_DIR + "r\course"
db_admin = db_DIR + r"\admin"
db_class_record = db_DIR + r"\class_record"
db_class_grade = db_DIR + r"\class_grade"
class Baseclass(object):
def __init__(self):
pass
def save(self,type,dict):
"""
school是一个字典格式,这个函数是对创建的学校进行存档
:param type:type输入的其实是db中的文件夹
:param dict:
:return:
"""
filename = uid.create_md()
dict['uid'] = filename #
file_path = "%s\%s"%(db_DIR,type) #type就是文件夹的名称
ab_file = "%s\%s"%(file_path,filename) #文件夹下的文件名称,filename是hash的id值
with open(ab_file,"wb") as f:
# dumps 将数据通过特殊的形式转换为只有python语言认识的字符串
f.write(pickle.dumps(dict))
print("-------",type,"创建成功","-------")
for key in dict:
print(key,":\t",dict[key])
def seek_list(self,type,list):
"""
此方法是将班级中的学生,学校的老师等列表进行存储
:param type: 学生,学校,班级中学生登记,班级等类别
:param list: 每种课程中的学生信息
:return:
"""
filename = uid.create_md()
file_path = "%s\%s" %(db_DIR,type)
ab_file = "%s\%s" %(file_path,filename)
with open(ab_file,"wb") as f: #二进制读入,二进制打开,最好的方式
f.write(pickle.dumps(list))
print("-------",type,"创建成功","--------")
for i in list: #i就是相关学生,老师的选课信息的字典
for key in i:
print(key,i[key])
print('\n')
return True
def open(self,type):
"""
此方法是将相关数据中的进行还原
:param type:数据类型
:return: 返回一个列表
"""
all_data = []
db_path = "%s\%s" %(db_DIR,type) #相对应的文件夹
for i in os.listdir(db_path): #直接就将文件显示出来了
if os.path.isfile(os.path.join(db_path,i)):
db_file = os.path.join(db_path,i) #变成绝对路径,os.path.join直接就把路径\合并了
with open(db_file,"rb") as f: #二进制打开
file_dict = pickle.load(f) #还原pickle的数据
all_data.append(file_dict) #可以把字典直接还原,返回的是列表
return all_data
class Admin(Baseclass):
def __init__(self):
super(Admin,self).__init__()
def create_school(self):
school_dict = {}
school_name = input("校名:")
school_address = input("地址:")
s1 = School(school_name,school_address)
school_dict["校名"] = s1.school_name
school_dict["地址"] = s1.school_address
Baseclass.save(self,"school",school_dict)
def create_teacher(self):
teacher_dict = {}
teacher_name = input("讲师姓名:")
teacher_salary = input("讲师工资:")
teacher_school = input("所属学校:")
t1 = Teacher(teacher_name,teacher_salary,teacher_school) #这些有点多余,其它也没有关联起来
teacher_dict["姓名"] = t1.teacher_name
teacher_dict["工资"] = t1.teacher_salary
teacher_dict["所属学校"] = t1.teacher_school
print(teacher_dict) #进行测试
Baseclass.save(self,"teacher",teacher_dict)
def create_student(self):
student_dict = {}
student_name = input("学员姓名:")
student_sex = input("学员性别:")
student_school = input("所属学校:")
student_classes = input("学员班级:")
# st1 = Student(student_name,student_sex,student_school,student_classes)
student_dict["姓名"] = student_name
student_dict["性别"] = student_sex
student_dict["学校"] = student_school
student_dict["班级"] = student_classes
Baseclass.save(self,"student",student_dict)
def create_course(self):
course_dict = {}
course_name = input("课程名:")
course_period = input("周期:")
course_prices = input("价格:")
c1 = Course(course_name,course_period,course_prices) #实例化Course类
course_dict["课程名"] = c1.course_name
阐述:
以上的就是pickle的基本使用,对文件目录文件读取写入等,在继承方面,指继承了基类的方法,注册什么的都是没有什么效果,最主要是类的继承比较繁琐,还是可以学习到一点东西。